question_answer

In the following figure if \[PQ=PR,\]then \[\angle p\] is

A)  \[50{}^\circ \]                      

B)  \[80{}^\circ \]   

C)  \[110{}^\circ \]                    

D)  None of these

Correct Answer: B

Solution :

(b):  \[\angle p=\angle q\] \[q+p+20{}^\circ =180{}^\circ \] \[\therefore \,\,\,2p+20{}^\circ =180{}^\circ \] \[\Rightarrow \,p=80{}^\circ \]