A) \[{{20}^{{}^\circ }}\]
B) \[{{155}^{{}^\circ }}\]
C) \[{{30}^{{}^\circ }}\]
D) \[{{45}^{{}^\circ }}\]
Correct Answer: B
Solution :
(b): \[\angle PQR=\angle QRS\] \[{{65}^{{}^\circ }}=\angle QRS\] \[{{65}^{{}^\circ }}=\angle QRL+\angle LRS\] Given \[{{65}^{{}^\circ }}={{40}^{{}^\circ }}+\angle LRS\] \[\Rightarrow \] \[\angle LRS={{25}^{{}^\circ }}\] \[\angle LRS+\angle RLM={{180}^{{}^\circ }}\] \[{{25}^{{}^\circ }}+\angle RLM={{180}^{{}^\circ }}\] \[\therefore \]\[RLM={{155}^{{}^\circ }}\]You need to login to perform this action.
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