question_answer

The maximum value of \[\mu =3x+4y\], subject to the conditions \[x+y\le 40,x+2y\le 60,x,y\ge 0\] is                                 [MP PET 2004]

A)                 130        

B)                 120

C)                 40          

D)                 140

Correct Answer: D

Solution :

                                Obviously, \[\mu =3x+4y\] will be maximum at \[(20,\,20)\]                                 \ Max\[\mu =3\times 20+4\times 20\]= \[60+80=140\].