A) \[12\frac{7}{19}\]
B) \[12\frac{1}{7}\]
C) \[12\frac{3}{5}\]
D) 12
Correct Answer: A
Solution :
The shaded region represent the feasible region, hence \[p=5{{x}_{1}}+3{{x}_{2}}\] Obviously it is maximum at \[\left( \frac{20}{19},\frac{45}{19} \right)\] Max \[p=5{{x}_{1}}+3{{x}_{2}}\]\[=5\left( \frac{20}{19} \right)+3\left( \frac{45}{19} \right)\] \[=\frac{100}{19}+\frac{135}{19}=\frac{235}{19}=12\frac{7}{19}\].You need to login to perform this action.
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