question_answer

The true statement for the graph of inequations \[3x+2y\le 6\] and \[6x+4y\ge 20\], is  

A)                 Both graphs are disjoint               

B)                 Both do not contain origin

C)                 Both contain point (1, 1)              

D)                 None of these

Correct Answer: A

Solution :

                The equations, corresponding to inequalities \[3x+2y\le 6\] and \[6x+4y\ge 20\], are \[3x+2y=6\] and \[6x+4y=20\]. So the lines represented by these equations are parallel. Hence the graphs are disjoint.