A) \[\left\{ \begin{align} & S=A+3 \\ & 4A+20S=132 \\ \end{align} \right.\]
B) \[\left\{ \begin{align} & A=S+3 \\ & 4A+20S=132 \\ \end{align} \right.\]
C) \[\left\{ \begin{align} & A=S+3 \\ & 20A+4S=132 \\ \end{align} \right.\]
D) \[\left\{ \begin{align} & A=S+3 \\ & A+S=132 \\ \end{align} \right.\]
Correct Answer: B
Solution :
Given, cost of an adult ticket = A cost of a child ticket = S \[\Rightarrow A=S+3\] Vihan spent 132 to buy tickets for 20 children and 4 adults \[\Rightarrow \] \[4A+20S=132\]
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