| (i) Find the temperature of the liquid in Fahrenheit if the temperature of the liquid is 313° K. |
| (ii) If the temperature is 158° F, then find the temperature in Kelvin. |
A)
(i) (ii) 112° F 150°K
B)
(i) (ii) 112° F 243° K
C)
(i) (ii) 104° F 343° K
D)
(i) (ii) 104°F 150°K
Correct Answer: C
Solution :
(i) Putting \[x=313{{\,}^{o}}K,\]in given equation, we get \[y=\frac{9}{5}(313-273)+32=\frac{9}{5}(40)+32\] \[=72+32={{104}^{o}}\,F\] (ii) Putting, \[y={{158}^{o}}\,F\]in given equation, we get, \[158=\frac{9}{5}(x-273)+32\] \[\Rightarrow \]\[158-32=\frac{9}{5}(x-273)\Rightarrow 126=\frac{9}{5}(x-273)\] \[\Rightarrow \]\[126\times \frac{5}{9}=x-273\Rightarrow x={{343}^{o}}K.\]
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