A) 16, 18
B) 14, 20
C) 15, 19
D) None of these
Correct Answer: B
Solution :
Let one part be \[x\] Then, other part be \[34-x\] According to question, we have \[\frac{4}{7}(x)=\frac{2}{5}(34-x)\Rightarrow \frac{4x}{7}=\frac{68}{5}-\frac{2x}{5}\] \[\Rightarrow \frac{4x}{7}+\frac{2x}{5}=\frac{68}{5}\Rightarrow \frac{20x+14x}{35}=\frac{68}{5}\] \[\Rightarrow \frac{34}{35}\times x=\frac{68}{5}\Rightarrow x=\frac{68}{5}\times \frac{35}{34}\] \[\Rightarrow x=2\times 7\Rightarrow x=14\] \[\therefore \] One part =14 and Other part =34-14=20You need to login to perform this action.
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