A) \[0\le y<a\]
B) \[0<y\le b\]
C) \[0<y>b\]
D) \[0\le y<b\]
Correct Answer: C
Solution :
(c): Let \[a,b\ge 0\]and \[x,y\ge 0\] \[\therefore \]\[a=bx+y\Rightarrow x=\frac{a-y}{b}\Rightarrow \frac{a-y}{b}>0\] \[\Rightarrow \]\[a-y>0\,\,\,\,\,\Rightarrow a>y\] \[\therefore \]\[0<y<a\]You need to login to perform this action.
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