JEE Main & Advanced Mathematics Differential Equations Question Bank Linear defferential equations

  • question_answer
    \[y+{{x}^{2}}=\frac{dy}{dx}\] has the solution          [EAMCET 2002]

    A)                 \[y+{{x}^{2}}+2x+2=c{{e}^{x}}\]          

    B)                 \[y+x+{{x}^{2}}+2=c{{e}^{2x}}\]

    C)                 \[y+x+2{{x}^{2}}+2=c{{e}^{x}}\]          

    D)                 \[{{y}^{2}}+x+{{x}^{2}}+2=c{{e}^{x}}\]

    Correct Answer: A

    Solution :

                       \[y+{{x}^{2}}=\frac{dy}{dx}\] Þ \[\frac{dy}{dx}-y={{x}^{2}}\]         This is the linear differential equation in y, where \[P=-1,\,Q={{x}^{2}}\]         I.F. \[={{e}^{\int{P.dx}}}\]\[={{e}^{\int{-dx}}}={{e}^{-x}}\]         Hence solution, \[y.\,(\text{I}\text{.F}).=\int{Q.(\text{I}\text{.F})\,dx+c}\]         Þ \[y{{e}^{-x}}=-{{x}^{2}}{{e}^{-x}}-2x{{e}^{-x}}-2{{e}^{-x}}+c\]                 Þ \[y+{{x}^{2}}+2x+2=c{{e}^{x}}\].


You need to login to perform this action.
You will be redirected in 3 sec spinner