A) \[y={{\log }_{e}}x+\frac{{{x}^{2}}}{2}+a\]
B) \[y=\frac{{{x}^{3}}}{3}+\frac{a}{x}\]
C) \[y={{x}^{2}}+ax\]
D) None of these
Correct Answer: C
Solution :
\[\frac{dy}{dx}-\frac{y}{x}=x\]; I.F. \[={{e}^{\int_{{}}^{{}}{-\frac{1}{x}dx}}}=\frac{1}{x}\] \[\therefore \] Solution is \[y\cdot \frac{1}{x}=\int_{{}}^{{}}{x\cdot \frac{1}{x}dx}\] Þ \[\frac{y}{x}=x+a\] Þ \[y={{x}^{2}}+ax\].
You need to login to perform this action.
You will be redirected in
3 sec
