JEE Main & Advanced Mathematics Differential Equations Question Bank Linear defferential equations

  • question_answer
    The solution of the differential equation \[\frac{dy}{dx}+2y\cot x=3{{x}^{2}}\text{cose}{{\text{c}}^{2}}x\]is

    A)                 \[y{{\sin }^{2}}x={{x}^{3}}+c\]

    B)                 \[y\sin x=c\]

    C)                 \[y\cos {{x}^{2}}=c\]       

    D)                 \[y\sin {{x}^{2}}=c\]

    Correct Answer: A

    Solution :

                       \[\frac{dy}{dx}+2\cot x.y=3{{x}^{2}}\text{cose}{{\text{c}}^{2}}x\]         This is a linear differential equation in y.         I.F.\[={{e}^{2\int_{{}}^{{}}{\cot xdx}}}={{e}^{2\log \sin x}}={{\sin }^{2}}x\]                    y. (I.F.)=\[\int_{{}}^{{}}{Q(\text{I}\text{.F}\text{.})\text{ }dx}\]                                 \[y.{{\sin }^{2}}x=\int_{{}}^{{}}{3{{x}^{2}}\text{cose}{{\text{c}}^{2}}x.{{\sin }^{2}}xdx={{x}^{3}}+c}\].


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