JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Line and Plane

  • question_answer
    If a plane passes through the point (1,1,1) and is perpendicular to the line \[\frac{x-1}{3}=\frac{y-1}{0}=\frac{z-1}{4}\], then its perpendicular distance from the origin is [MP PET 1998]

    A)            \[\frac{3}{4}\]

    B)            \[\frac{4}{3}\]

    C)            \[\frac{7}{5}\]

    D)            1

    Correct Answer: C

    Solution :

                       According to \[\frac{A}{l}=\frac{B}{m}=\frac{C}{n},\] direction ratio of plane are respectively (3, 0, 4).            Equation of plane passing through point (1, 1, 1) is            \[\Rightarrow \,\,A(x-{{x}_{1}})+B\,(y-{{y}_{1}})+C\,(z-{{z}_{1}})=0\]            \[\Rightarrow \,\,3\,(x-1)+0\,(y-1)+4\,(z-1)=0\]\[\Rightarrow \,\,3x+4z-7=0\]            Normal form of plane is, \[\frac{3x}{5}+\frac{4z}{5}=\frac{7}{5}\]            \[\therefore \] Perpendicular distance from \[(0,\,\,0,\,\,0)=\frac{7}{5}\].


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