A) 9
B) 1
C) 2
D) 3
Correct Answer: D
Solution :
Obviously the line and the plane are parallel, so to find the distance between the line and the plane, take any point on the line i.e., (1, ? 2, 1). Now the perpendicular distance of the point (1, ? 2, 1) from the plane will be the required distance. Hence distance \[=\left| \,\frac{2\,(1)+2\,(-2)\,-1\,(1)-6}{\sqrt{{{2}^{2}}+{{2}^{2}}+{{1}^{2}}}}\, \right|=\frac{9}{\sqrt{9}}=3\].
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