A) \[x+y+z-15=0\]
B) \[x-y+z-15=0\]
C) \[x-y-z-15=0\]
D) \[x+y+z+15=0\]
Correct Answer: A
Solution :
Mid-point of (2,3,4) and (6, 7, 8) is (4, 5, 6). This lies on \[x+y+z-15=0.\]Hence this is the required plane.
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