JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of mass action

  • question_answer
    The active mass of 64 gm of HI in a two litre flask would be [CPMT 1979]

    A)                 2             

    B)                 1

    C)                 5             

    D)                 0.25

    Correct Answer: D

    Solution :

           \[[HI]=\frac{64gm}{128\times 2\,litre}=0.25\]                                 Active mass is the concentration in moles/litre.


You need to login to perform this action.
You will be redirected in 3 sec spinner