A) 1,2,2
B) 2,2,1
C) 1,1,2
D) 2,1,2
Correct Answer: C
Solution :
\[{{N}_{2}}+3{{H}_{2}}\] ⇌ \[2N{{H}_{3}}\] ?.. (i) at \[t=0\] \[56\,gm\]\[8gm\] \[0gm\] = \[2mole\] \[4mole\] \[0mole\] at equilibrium \[2-1\] \[4-3\] \[34gm\] =\[1\,mole\] = \[1\,mole\] = \[2\,mole\] According to eq. (i) 2 mole of ammonia are present & to produce 2 mole of \[N{{H}_{3}}\], we need 1 mole of \[{{N}_{2}}\] and 3 mole of \[{{H}_{2}}\] hence \[2-1=1\] mole of \[{{N}_{2}}\] and \[4-3=1\] mole of \[{{H}_{2}}\] are present at equilibrium in vessel.
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