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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    In the reaction, \[A+B\]⇌\[2C\], at equilibrium, the concentration of A and B is \[0.20\,\,mol\,\,{{l}^{-1}}\] each and that of C was found to be \[0.60\,\,mol\,\,{{l}^{-1}}\]. The equilibrium constant of the reaction is                                                          [MH CET 2000]

    A)                 2.4         

    B)                 18

    C)                 4.8         

    D)                 9

    Correct Answer: D

    Solution :

             \[A+B\] ⇌ \[2\,C\]                                 \[{{K}_{c}}=\frac{{{[C]}^{2}}}{[A]\,\,[B]}=\frac{{{[0.6]}^{2}}}{[0.2]\,\,[0.2]}=9\]


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