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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    When 3 mole of A and 1 mole of B are mixed in 1 litre vessel the following reaction takes place \[{{A}_{(g)}}+{{B}_{(g)}}\]⇌\[2{{C}_{(g)}}\]. 1.5 moles of C are formed. The equilibrium constant for the reaction is     [MP PMT 2000]

    A)                 0.12       

    B)                 0.25

    C)                 0.50       

    D)                 4.0

    Correct Answer: D

    Solution :

           \[\underset{(3-0.75)}{\mathop{A}}\,+\underset{(1-0.75)}{\mathop{B}}\,\to \underset{1.5}{\mathop{2C}}\,\]                                 \[K=\frac{{{[C]}^{2}}}{[A]\,\,[B]}=\frac{{{(1.5)}^{2}}}{2.25\times 0.25}=\frac{2.25}{2.25\times 0.25}=4.0\].


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