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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    On a given condition, the equilibrium concentration of \[HI,\,{{H}_{2}}\] and \[{{I}_{2}}\] are 0.80, 0.10 and 0.10 mole/litre. The equilibrium constant for the reaction \[{{H}_{2}}+{{I}_{2}}\] ⇌ \[2HI\]  will be            [MP PET 1986]

    A)                 64          

    B)                 12

    C)                 8             

    D)                 0.8

    Correct Answer: A

    Solution :

               \[{{H}_{2}}+{{I}_{2}}\]⇌ 2HI; [HI] = 0.80, \[[{{H}_{2}}]=0.10\], \[[{{I}_{2}}]=0.10\]                                 \[{{K}_{c}}=\frac{{{[HI]}^{2}}}{[{{H}_{2}}]\,\,[{{I}_{2}}]}=\frac{0.80\times 0.80}{0.10\times 0.10}=64\]


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