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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    An equilibrium mixture of the reaction \[2{{H}_{2}}S(g)\]⇌\[2{{H}_{2}}(g)+{{S}_{2}}(g)\] had 0.5 mole \[{{H}_{2}}S\], 0.10 mole \[{{H}_{2}}\] and 0.4 mole \[{{S}_{2}}\] in one litre vessel. The value of equilibrium constant \[(K)\] in mole litre-1 is [AIIMS 1998; IIT 1992; AFMC 1999; UPSEAT 2001]

    A)                 0.004    

    B)                 0.008

    C)                 0.016    

    D)                 0.160

    Correct Answer: C

    Solution :

    \[K=\frac{{{[{{H}_{2}}]}^{2}}[{{S}_{2}}]}{{{[{{H}_{2}}S]}^{2}}}=\frac{{{[0.10]}^{2}}[0.4]}{{{[0.5]}^{2}}}=0.016\]


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