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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    A reaction is \[A+B\to C+D\]. Initially we start with equal concentration of \[A\] and \[B\]. At equilibrium we find the moles of \[C\] is two times of \[A\]. What is the equilibrium constant of the reaction    [BHU 1998; KCET 2000]

    A)                 4             

    B)                 2

    C)                 \[1/4\]

    D)                 \[1/2\]

    Correct Answer: A

    Solution :

                                     A+ B ⇌ C+ D                    at equilibrium   a  a     2a  2a                                 \[K=\frac{2a\times 2a}{a\times a}=4\]


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