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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    In a chemical equilibrium, the rate constant of the backward reaction is \[7.5\times {{10}^{-4}}\] and the equilibrium constant is 1.5. So the rate constant of the forward reaction is    [KCET 1989]

    A)                 \[5\times {{10}^{-4}}\]  

    B)                 \[2\times {{10}^{-3}}\]

    C)                 \[1.125\times {{10}^{-3}}\]         

    D)                 \[9.0\times {{10}^{-4}}\]

    Correct Answer: C

    Solution :

           \[{{K}_{c}}=\frac{{{K}_{f}}}{{{K}_{b}}}\]                 \[{{K}_{f}}={{K}_{c}}\times {{K}_{b}}=1.5\times 7.5\times {{10}^{-4}}\]\[=1.125\times {{10}^{-3}}\]


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