A) Dissociation decreases
B) Dissociation increases
C) Dissociation does not change
D) None of these
Correct Answer: A
Solution :
\[PC{{l}_{5}}(g)\] ⇌\[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\] For this reaction \[\Delta n=2-1=1\] Value of \[\Delta n\] is positive so the dissociation of \[PC{{l}_{5}}\] take forward by decrease in pressure & by increase in pressure the dissociation of \[PC{{l}_{5}}\] decrease.You need to login to perform this action.
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