A) 1.0
B) 2.0
C) 3.0
D) 4.0
Correct Answer: D
Solution :
\[{{K}_{1}}\]for reaction 2HI ⇌\[{{H}_{2}}+{{I}_{2}}\]is 0.25 \[{{K}_{2}}\] for reaction \[{{H}_{2}}+{{I}_{2}}\]⇌ 2HI will be \[{{K}_{2}}=\frac{1}{{{K}_{1}}}=\frac{1}{0.25}=4\] Because IInd reaction is reverse of Ist.
You need to login to perform this action.
You will be redirected in
3 sec
