A) 6.65 atm
B) 0.665 atm
C) 0.0665 atm
D) 66.5 atm
Correct Answer: B
Solution :
\[{{K}_{p}}=\frac{{{p}^{2}}}{4};\,\,0.11=\frac{{{p}^{2}}}{4}\Rightarrow {{p}^{2}}=0.44\] or \[p=\sqrt{0.44}=0.66444\approx \,0.665\,atm\]You need to login to perform this action.
You will be redirected in
3 sec