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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Kp and Kc Relationship and Characteristics of K

  • question_answer
    If for \[{{H}_{2}}_{(g)}+\frac{1}{2}{{S}_{2(S)}}\]⇌\[{{H}_{2}}{{S}_{(g)}}\] and \[{{H}_{2(g)}}+B{{r}_{2(g)}}\]⇌\[2HB{{r}_{(g)}}\] The equilibrium constants are K1 and K2 respectively, the reaction \[B{{r}_{2}}_{(g)}+{{H}_{2}}{{S}_{(g)}}\]⇌\[2HB{{r}_{(g)}}+\frac{1}{2}{{S}_{2(S)}}\] would have equilibrium constant                                              [MP PMT 2001]

    A)                 \[{{K}_{1}}\ \times \ {{K}_{2}}\]

    B)                         \[{{K}_{1}}/{{K}_{2}}\]

    C)                 \[{{K}_{2}}/{{K}_{1}}\]  

    D)                 \[K_{2}^{2}/{{K}_{1}}\]

    Correct Answer: C

    Solution :

               \[{{K}_{1}}=\frac{[{{H}_{2}}S]}{[{{H}_{2}}]\,\,{{[{{S}_{2}}]}^{{1}/{2}\;}}}\]; \[{{K}_{2}}=\frac{{{[HBr]}^{2}}}{[{{H}_{2}}]\,\,[B{{r}_{2}}]}\]                                 \[{{K}_{3}}=\frac{{{[HBr]}^{2}}\times {{[{{S}_{2}}]}^{{1}/{2}\;}}}{[B{{r}_{2}}]\,\times [{{H}_{2}}S]}\]; \[\frac{{{K}_{2}}}{{{K}_{1}}}={{K}_{3}}\]


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