A) \[{{K}_{P}}=({{P}_{CaO}}+{{P}_{C{{O}_{2}}}}/{{P}_{CaC{{O}_{3}}}})\]
B) \[{{K}_{P}}={{P}_{C{{O}_{2}}}}\]
C) \[{{K}_{P}}\times ({{P}_{CaO}}\times {{P}_{C{{O}_{2}}}}).{{P}_{CaC{{O}_{3}}}}\]
D) \[\frac{{{K}_{p}}[CaO][C{{O}_{2}}]}{[CaC{{O}_{3}}]}\]
Correct Answer: B
Solution :
\[CaC{{O}_{3(s)}}\]⇌ \[Ca{{O}_{(s)}}+C{{O}_{2(g)}}\] \[{{K}_{p}}={{P}_{C{{O}_{2}}}}\] Solid molecule does not have partial pressure so in calculation of \[{{K}_{p}}\]only \[{{P}_{C{{O}_{2}}}}\]is applicable.You need to login to perform this action.
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