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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Kp and Kc Relationship and Characteristics of K

  • question_answer
    At 490°C, the equilibrium constant for the synthesis of HI is 50, the value of K for the dissociation of HI will be [KCET 2000]

    A)                 20.0       

    B)                 2.0

    C)                 0.2         

    D)                 0.02

    Correct Answer: D

    Solution :

             K for dissociation of HI =?            \[{{H}_{2}}+{{I}_{2}}\]⇌ 2HI                                 \[{{K}_{a}}=50\], \[{{K}_{b}}=\frac{1}{50}=0.02\]


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