A) 8 Watt
B) 4 Watt
C) 2 Watt
D) None of the above
Correct Answer: C
Solution :
\[{{P}_{\text{max}}}=\frac{{{E}^{2}}}{4r}=\frac{{{(2)}^{2}}}{4\times 0.5}=2\,W\]
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