JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Kirchhoff's Law, Cells

  • question_answer
    A new flashlight cell of e.m.f. 1.5 volts gives a current of 15 amps, when connected directly to an ammeter of resistance \[0.04\,\Omega \]. The internal resistance of cell is [MP PET 1994]

    A)                    \[0.04\,\Omega \]

    B)                                      \[0.06\,\Omega \]

    C)                    \[0.10\,\Omega \]      

    D)            \[10\,\Omega \]

    Correct Answer: B

    Solution :

               Let the internal resistance of cell be r, then \[i=\frac{E}{R+r}\] Þ \[15=\frac{1.5}{0.04+r}\] Þ \[r=0.06\Omega \]


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