A) \[P=\frac{2}{3}E\]
B) \[P=\frac{3}{2}E\]
C) \[P=\frac{1}{2}E\]
D) \[P=2E\]
Correct Answer: A
Solution :
KE \[=\frac{3}{2}RT=\frac{3}{2}PV\] \[\therefore P=\frac{2}{3}\frac{E}{V}\] for unit volume (V = 1) Þ \[P=\frac{2}{3}E\]You need to login to perform this action.
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