A) 2.5 m
B) 5 m
C) 7.5 m
D) 10 m
Correct Answer: D
Solution :
Kinetic energy of the cylinder will go against friction \[\therefore \] \[\frac{1}{2}m{{v}^{2}}\]=\[\mu \ mgs\]Þ \[s=\frac{{{u}^{2}}}{2\mu \ g}=\frac{{{(10)}^{2}}}{2\times (0.5)\times 10}=10\,m\]
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