A) \[\frac{v_{0}^{2}}{2\mu g}\]
B) \[\frac{{{v}_{0}}}{\mu g}\]
C) \[{{\left( \frac{{{v}_{0}}}{\mu g} \right)}^{2}}\]
D) \[\frac{{{v}_{0}}}{\mu }\]
Correct Answer: A
Solution :
Retarding force \[F=ma=\mu \,R=\mu \ mg\] \[\therefore \] \[a=\mu g\] Now from equation of motion \[{{v}^{2}}={{u}^{2}}-2as\] \[\Rightarrow \ 0={{u}^{2}}-2as\] Þ \[s=\frac{{{u}^{2}}}{2a}=\frac{{{u}^{2}}}{2\mu \ g}\] \[\therefore \] \[=\frac{v_{0}^{2}}{2\mu \,g}\]
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