A) \[\frac{g}{6.4}\]
B) 0.64 g
C) \[\frac{g}{32}\]
D) 0.2 g
Correct Answer: D
Solution :
Weight of the body = 64N so mass of the body\[m=6.4\ kg\],\[{{\mu }_{s}}=0.6\], \[{{\mu }_{k}}=0.4\] Net acceleration \[=\frac{\text{Applied force -Kinetic friction}}{\text{Mass of the body}}\] \[=\frac{{{\mu }_{s}}mg-{{\mu }_{k}}mg}{m}=({{\mu }_{s}}-{{\mu }_{k}})g=(0.6-0.4)g=0.2\,g\]
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