JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Kepler's Laws of Planetary Motion

  • question_answer
    The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun [CBSE PMT 1997; BHU 2001]

    A) 2         

    B)             3

    C)             4

    D)             5

    Correct Answer: C

    Solution :

                    \[\frac{{{T}_{A}}}{{{T}_{B}}}={{\left( \frac{{{r}_{A}}}{{{r}_{B}}} \right)}^{3/2}}\]\[\Rightarrow 8={{\left( \frac{{{r}_{A}}}{{{r}_{B}}} \right)}^{3/2}}\]\[\Rightarrow {{r}_{A}}={{(8)}^{2/3}}{{r}_{B}}\]\[=4{{r}_{B}}.\]


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