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JEE Main & Advanced Physics Semiconducting Devices Question Bank Junction Transistor

  • question_answer
    If a = 0.98 and current through emitter ie = 20 mA, the value of b is                                          [DPMT 2002]

    A)            4.9 

    B)            49

    C)            96  

    D)            9.6

    Correct Answer: B

    Solution :

               \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.98}{1-0.98}\]=49.


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