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JEE Main & Advanced Physics Semiconducting Devices Question Bank Junction Transistor

  • question_answer
    In the CB mode of a transistor, when the collector voltage is changed by 0.5 volt. The collector current changes by 0.05 mA. The output resistance will be            [Pb. PMT 2003]

    A)            10 kW                                      

    B)            20 kW

    C)            5 kW                                        

    D)            2.5 kW

    Correct Answer: A

    Solution :

                       Here \[\Delta {{V}_{c}}=0.5\,V\], \[\Delta {{i}_{c}}\]=0.05mA = 0.05 ´ 10?3A                    Output resistance is given by                    \[{{R}_{out}}=\frac{\Delta {{V}_{c}}}{\Delta {{i}_{c}}}=\frac{0.5}{0.05\times {{10}^{-3}}}={{10}^{4}}\Omega \] = 10kW.


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