A) \[\alpha =\frac{\beta }{1-\beta }\]
B) \[\alpha =\frac{\beta }{1+\beta }\]
C) \[\alpha =\frac{1-\beta }{\beta }\]
D) \[\alpha =\frac{1+\beta }{\beta }\]
Correct Answer: B
Solution :
\[{{i}_{e}}={{i}_{b}}+{{i}_{c}}\]\[\Rightarrow \frac{{{i}_{e}}}{{{i}_{c}}}=\frac{{{i}_{b}}}{{{i}_{c}}}+1\]\[\Rightarrow \frac{1}{\alpha }=\frac{1}{\beta }+1\]\[\Rightarrow \alpha =\frac{\beta }{(1+\beta )}\].
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