A) 0.04 mA
B) 1.96 mA
C) 0.98 mA
D) 2 mA
Correct Answer: A
Solution :
\[\Delta {{i}_{c}}=\alpha \,\Delta {{i}_{e}}=0.98\times 2=1.96\,mA\] \ \[\Delta {{i}_{b}}=\Delta {{i}_{e}}-\Delta {{i}_{c}}=2-1.96=0.04\,mA\].
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