A) 9.9
B) 99
C) 990
D) 9900
Correct Answer: C
Solution :
Voltage gain = b ´ Resistance gain \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.99}{(1-0.99)}=99\] Resistance gain \[=\frac{10\times {{10}^{3}}}{{{10}^{3}}}=10\] Þ Voltage gain = 99 ´ 10 = 990.
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