A) 80 ´ 250 mA
B) (250 ? 80) mA
C) (250 + 80) mA
D) 250/80 mA
Correct Answer: A
Solution :
Current gain \[\beta =\frac{\Delta {{i}_{c}}}{\Delta {{i}_{b}}}\]\[\Rightarrow \Delta {{i}_{c}}=\beta \times \Delta {{i}_{b}}\]= 80 ´ 250 mA.You need to login to perform this action.
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