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JEE Main & Advanced Physics Semiconducting Devices Question Bank Junction Transistor

  • question_answer
    In an NPN transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, the emitter current (iE) and base current (iB) are given by     [KCET 2001]

    A)            iE = ? 1 mA, iB = 9 mA         

    B)            iE = 9 mA, iB = ? 1 mA         

    C)            iE = 1 mA, iB = 11 mA          

    D)            iE = 11 mA, iB = 1 mA

    Correct Answer: D

    Solution :

                       \[{{i}_{C}}=\frac{90}{100}\times {{i}_{E}}\]Þ 10 = 0.9 ´ iE = 11mA Also \[{{i}_{E}}={{i}_{B}}+{{i}_{C}}\]\[\Rightarrow {{i}_{B}}=11-10=1mA.\]


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