2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Semiconducting Devices

JEE Main & Advanced Physics Semiconducting Devices Question Bank Junction Transistor

  • question_answer
    For a common base configuration of PNP transistor \[\frac{{{l}_{C}}}{{{l}_{E}}}=0.98\] then maximum current gain in common emitter configuration will be                                                    [CBSE PMT 2002]

    A)            12  

    B)            24

    C)            6    

    D)            5

    Correct Answer: B

    Solution :

               \[\beta =\frac{\alpha }{1-\alpha }=\frac{0.96}{1-0.96}\]=24.


You need to login to perform this action.
You will be redirected in 3 sec spinner