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question_answer1) When a graph is plotted between log \[x/m\] and log p, it is straight line with an angle \[45{}^\circ \] and intercept 0.3010 on y-axis. If initial pressure is 0.3 atm, what will be the amount of gas adsorbed per gm of adsorbent.
question_answer2) 0.025 gm of starch sol is required to prevent coagulation of 10 ml gold sol when 1 ml of 10% \[NaCl\] solution is added. What is gold number of starch sol-
question_answer3) Gold number of haemoglobin is 0.03. Hence 100 ml of gold sol will require haemoglobin so that gold is not coagulated by 10 ml of 10% \[NaCl\] solution-
question_answer4) The pressure of the gas was found to decrease from 720 to 480 mm. When 5g of sample of activated charcoal was kept in a flask of one litre capacity maintained at \[27{}^\circ C\] . If the density of characoal is 1.25 gm/mL. The volume of gas adsorbed per gm of charcoal at 480 mm of Hg is-
question_answer5) Coagulation value of the electrolytes \[AlC{{l}_{3}}\] and \[NaCl\] for \[A{{s}_{2}}{{S}_{3}}\] sol are 0.093 and 52 respectively. How many times \[AlC{{l}_{3}}\] has greater coagulating power than \[NaCl\].
question_answer6) Graph between log \[x/m\] and log p is a straight line inclined at an angle of \[45{}^\circ \]. When pressure is 0.5 atm and ln k = 0.693, the amount of solute adsorbed per gm of adsorbent will be:
question_answer7) Finely divided catalyst has greater surface area and has greater catalytic activity than the compact solid. If a total surface area of 6291456 \[c{{m}^{2}}\] is required for adsorption of gaseous reactants in a catalysed reaction, then how many splits should be made of a cube exactly 1 cm in length. Given: After each split new cubes of equal dimensions are formed.
question_answer8) Volume of \[{{N}_{2}}\] at NTP required to form a monolayer on the surface of iron catalyst is 8.15 ml/g of the adsorbent. What will be the surface area of the 100 g adsorbent if each nitrogen molecule occupies\[16\times {{10}^{-22}}{{m}^{2}}\] .
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