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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Isothermal Process

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    The volume of an ideal gas is 1 litre and its pressure is equal to 72cm of mercury column. The volume of gas is made 900 cm3 by compressing it isothermally. The stress of the gas will be        [UPSEAT 1999]

    A)            8 cm (mercury)                   

    B)             7 cm (mercury)

    C)            6 cm (mercury)                   

    D)             4 cm (mercury)

    Correct Answer: A

    Solution :

                       For isothermal process \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\]                    Þ \[{{P}_{2}}=\frac{{{P}_{1}}{{V}_{1}}}{{{V}_{2}}}=\frac{72\times 1000}{900}\]=80 cm            Stress \[\Delt P={{P}_{2}}-{{P}_{1}}=80-72=8cm\]


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