A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{2}\]
C) \[\frac{2\pi }{3}\]
D) \[\frac{-2\pi }{3}\]
Correct Answer: A
Solution :
\[\theta ={{\sin }^{-1}}[\sin (-{{600}^{o}})]\] Þ \[\theta ={{\sin }^{-1}}[-(\sin {{240}^{o}})]\]\[={{\sin }^{-1}}[-\sin ({{180}^{o}}+{{60}^{o}})]\] Þ \[\theta ={{\sin }^{-1}}\sin {{60}^{o}}\] \[={{\sin }^{-1}}\left[ \sin \left( \frac{\pi }{3} \right) \right]=\frac{\pi }{3}\].
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