A) 1
B) 0
C) \[\frac{4}{5}\]
D) \[\frac{1}{5}\]
Correct Answer: D
Solution :
\[{{\sin }^{-1}}\frac{1}{5}+{{\cos }^{-1}}x=\frac{\pi }{2}\] \[\therefore \,\,{{\sin }^{-1}}\frac{1}{5}=\frac{\pi }{2}-{{\cos }^{-1}}x={{\sin }^{-1}}x\] \[\therefore \,\,\,x=\frac{1}{5}\].
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