A) a
B) 2a
C) \[2{{a}^{2}}\]
D) \[4{{a}^{2}}\]
Correct Answer: D
Solution :
Resultant amplitude \[A=\sqrt{{{a}^{2}}+{{a}^{2}}+2aa\cos \varphi }\]\[=\sqrt{4{{a}^{2}}{{\cos }^{2}}\,\left( \frac{\varphi }{2} \right)}\] \[\because \] \[n=\frac{pv}{2l}\]Þ \[I\propto 4{{a}^{2}}\]
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