A) 1
B) 9
C) 4
D) 16
Correct Answer: B
Solution :
\[{{a}_{1}}=5,\,\,{{a}_{2}}=10\] \[\Rightarrow \]\[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{({{a}_{1}}+{{a}_{2}})}^{2}}}{{{({{a}_{1}}-{{a}_{2}})}^{2}}}={{\left( \frac{5+10}{5-10} \right)}^{2}}=\frac{9}{1}\]You need to login to perform this action.
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